Index of programs:Set 1

Amstrong numbers upto 1000

Find second largest only

Largest of given set of numbers using sorting method

Find cosine of x >precision 4 decimal digits

Find value of e^x >precision 4 decimal digits

Find sum of two time quantities and display in correct format using Class scopes

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Program1:
#include<iostream.h> #include<conio.h> #include<math.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : To print amstrong numbers upto 1000 Meant For : Plus Two students,Kerala */ int amstrong(int); int amstrong(int a) { int x=a; int s=0; int re; while(x!=0) { re=x%10; s=s+pow(re,3); x=x/10; } if(s==a) return(0); else return(1); } void main() { clrscr(); cout<<"\n \t Amstrong numbers between 1 and 1000\n"; for(int i=1;i<=1000;i++) if(amstrong(i)==0) cout<<"\t\t"<<i<<"\n"; cout<<"\n Press any key to continue"; getch(); }

Program 2:

#include<iostream.h> #include<conio.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : To find second largest only Meant For : Plus Two students,Kerala */ void main() { int n,i,j,k,t,a[50]; clrscr(); cout<<"\n Enter limit:"; cin>>n; for(i=1;i<=n;i++) cin>>a[i]; for(i=1;i<=n-1;i++) for(j=1;j<=n-i;j++) if(a[j]>a[j+1]) { t=a[j]; a[j]=a[j+1]; a[j+1]=t; } for(i=n;i<=1;i--) { k=a[n]-a[i]; if(k!=0) break; } if(i>1) cout<<"\n Second largest is"<<a[i]; else cout<<"\n No Second largest"; cout<<"\n Press any key to continue"; getch(); }

Program 3:

#include<iostream.h> #include<conio.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : Largest number among set of numbers using sorting technique Meant For : Plus Two students,Kerala */ void main() { clrscr(); int a[50],n,i,j,t; cout<<"\n Enter limit:"; cin>>n; cout<<"\n Enter number:"; for(i=1;i<=n;i++) cin>>a[i]; for(i=1;i<=n-1;i++) for(j=1;j<=n-i;j++) if(a[j]>a[j+1]) { t=a[j]; a[j]=a[j+1]; a[j+1]=t; } for(i=n-1;i>=1;i--) if(a[n]!=a[i]) break; if(i>1) cout<<"\n Largest is:"<<a[n]; else cout<<"\n All numbers are equal"; cout<<"\n Press any key to continue"; getch(); }

Program 4:

#include<iostream.h> #include<conio.h> #include<math.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : To find cosine value of x Meant For : Plus Two students,Kerala */ void main() { float x,n; clrscr(); cout<<"\n Enter value of x:"; cin>>x; n=(3.14/180)*x; float t,s=1; t=-n*n/2; for(int i=3;fabs(t)>.0001;i=i+2) { s+=t; t=-(t*n*n)/(i*(i+1)); } cout<<"\n The cosine series sum is"<<s; cout<<"\n Press any key to continue"; getch(); }

Program 5:

#include<iostream.h> #include<conio.h> #include<math.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : To find the value of e^x Meant For: Plus Two students,Kerala */ void main() { float s=1,x,t; clrscr(); cout<<"\n Enter value of x"; cin>>x; t=x; for(int i=1;fabs(t)>.0001;i++) { s=s+t; t=(t*x)/(i*(i+1)); } cout<<"\n The value of e^x is"<<s; cout<<"\n Press any key to continue"; getch(); }

Program 6:

#include<iostream.h> #include<conio.h> /* Author : Rohith.R Email : rrohithr@gmail.com Category : Begineer Program : To accept 2 times and return its sum using class Meant For : Plus Two students,Kerala */ class TIMER { int hrs,mts,secs; public: void reader(); void printer(); TIMER operator+(TIMER); }; void TIMER::reader() { cout<<"\n Enter Hour :";cin>>hrs; cout<<"\n Enter Minutes:";cin>>mts; cout<<"\n Enter Seconds:";cin>>secs; } void TIMER::printer() { cout<<"Time:"<<hrs<<"hrs :"<<mts<<"mts :"<<secs<< "secs"; } TIMER TIMER::operator+(TIMER t1) { TIMER t2; t2.secs=secs+t1.secs; t2.mts =t2.secs/60; t2.secs=t2.secs%60; t2.mts+=mts+t1.mts; t2.hrs=t2.mts/60; t2.mts=t2.mts%60; t2.hrs+=hrs+t1.hrs; return(t2); } void main() { cout<<"\n Enter details of Ist time:"; TIMER d1,d2,d3; d1.reader(); cout<<"\n Enter details of 2nd time:"; d2.reader(); clrscr(); d3=d1+d2; d1.printer(); cout<<"\n +\n"; d2.printer(); cout<<"\n ----------------------\n"; d3.printer(); }

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